x^2+20x-40=4

Solution for x^2+20x-40=4 equation:

Simplifying
x2 + 20x + -40 = 4

Reorder the terms:
-40 + 20x + x2 = 4

Solving
-40 + 20x + x2 = 4

Solving for variable 'x'.

Reorder the terms:
-40 + -4 + 20x + x2 = 4 + -4

Combine like terms: -40 + -4 = -44
-44 + 20x + x2 = 4 + -4

Combine like terms: 4 + -4 = 0
-44 + 20x + x2 = 0

Factor a trinomial.
(-22 + -1x)(2 + -1x) = 0

Subproblem 1
Set the factor '(-22 + -1x)' equal to zero and attempt to solve:

Simplifying
-22 + -1x = 0

Solving
-22 + -1x = 0

Move all terms containing x to the left, all other terms to the right.

Add '22' to each side of the equation.
-22 + 22 + -1x = 0 + 22

Combine like terms: -22 + 22 = 0
0 + -1x = 0 + 22
-1x = 0 + 22

Combine like terms: 0 + 22 = 22
-1x = 22

Divide each side by '-1'.
x = -22

Simplifying
x = -22
Subproblem 2
Set the factor '(2 + -1x)' equal to zero and attempt to solve:

Simplifying
2 + -1x = 0

Solving
2 + -1x = 0

Move all terms containing x to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + -1x = 0 + -2

Combine like terms: 2 + -2 = 0
0 + -1x = 0 + -2
-1x = 0 + -2

Combine like terms: 0 + -2 = -2
-1x = -2

Divide each side by '-1'.
x = 2

Simplifying
x = 2
Solution
x = {-22, 2}